3(a²-4a+3)-5(5a²-a+2)
原式=3a²-12a+9-25a²+5a-10
=-22a²-7a-1
解:原式=3a²-12a+9-25a²+5a-10
=-22a²-7a-1
3(a²-4a+3)-5(5a²-a+2)=3a*a-12a+9-25a*a+5a-10=-22a*a-7a-1
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原式=3a²-12a+9-25a²+5a-10
=-22a²-7a-1
解:原式=3a²-12a+9-25a²+5a-10
=-22a²-7a-1
3(a²-4a+3)-5(5a²-a+2)=3a*a-12a+9-25a*a+5a-10=-22a*a-7a-1