仓库里有一批化肥,第1是取出化肥的2/5,第2次取出化肥的1/3少12袋,这时仓库里还剩24袋,化肥共有多少袋?
(24-12)÷(1-2/5-1/3)
=12÷(15/15-6/15-5/15)
=12÷(4/15)
=12×15÷4
=3×15
=45
答:化肥原来共有45袋
(24-12)÷(1-1/3-2/5)=45(袋)
应有四十五袋的了
设共有x袋
2/5x+1/3*(1-2/5)x-12=24
x=60
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(24-12)÷(1-2/5-1/3)
=12÷(15/15-6/15-5/15)
=12÷(4/15)
=12×15÷4
=3×15
=45
答:化肥原来共有45袋
(24-12)÷(1-1/3-2/5)=45(袋)
应有四十五袋的了
设共有x袋
2/5x+1/3*(1-2/5)x-12=24
x=60