已知a²+b²=1,a-b=1/2,则a+b四次方-=
a-b=1/2
(a-b)^2=1/4
a^2-2ab+b^2=1/4
1-2ab=1/4
2ab=3/4
ab=3/8
(a+b)^4
=[(a+b)^]^2
=(a^2+2ab+b^2)^2
=(1+2*3/8)^2
=(7/4)^2
=49/16
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a-b=1/2
(a-b)^2=1/4
a^2-2ab+b^2=1/4
1-2ab=1/4
2ab=3/4
ab=3/8
(a+b)^4
=[(a+b)^]^2
=(a^2+2ab+b^2)^2
=(1+2*3/8)^2
=(7/4)^2
=49/16