对于任何整数m，多项式（4m+5）^2-9都能（）A.被8整除B.被m整除C.被m-1整除D.被2m-1整除
(4m+5)²-9
=(4m+5)²-3²
=(4m+5+3)(4m+5-3)
=(4m+8)(4m+2)
=8(m+2)(2m+1)
选择 A
//
若"除"是"除以"
[(-2xyz)²*2(x^4)y³z]y
=4x²y²z²*2(x^4)y³z*y
=8(x^6)(y^6)*z³
=(2x²y²z)³
选择 C
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(4m+5)²-9
=(4m+5)²-3²
=(4m+5+3)(4m+5-3)
=(4m+8)(4m+2)
=8(m+2)(2m+1)
选择 A
//
[(-2xyz)²*2(x^4)y³z]y
=4x²y²z²*2(x^4)y³z*y
=8(x^6)(y^6)*z³
=(2x²y²z)³
选择 C
上一篇：提问删不下去