f(x+y,x-2y)=xx+yy,则f(x,y)=
(1°)f(x+y,x-2y)=x²+y²
设 x+y=p① x-2y=q②
①-② 3y=p-q y=(p-q)/3③
①-③ x=p-(p-q)/3=(2p+q)/3④
代入1°
f(p,q)=(2p+q)²/3²+(p-q)²/3²
=(5p²+2pq+2q²)/9
∴ f(x,y)=(5x²+2xy+2y²)/9
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(1°)f(x+y,x-2y)=x²+y²
设 x+y=p① x-2y=q②
①-② 3y=p-q y=(p-q)/3③
①-③ x=p-(p-q)/3=(2p+q)/3④
代入1°
f(p,q)=(2p+q)²/3²+(p-q)²/3²
=(5p²+2pq+2q²)/9
∴ f(x,y)=(5x²+2xy+2y²)/9